0.04x^2-6=0

Solution for 0.04x^2-6=0 equation:

0.04x^2-6=0

a = 0.04; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·0.04·(-6)
Δ = 0.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.96}}{2*0.04}=\frac{0-\sqrt{0.96}}{0.08}
=-\frac{\sqrt{}}{0.08}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.96}}{2*0.04}=\frac{0+\sqrt{0.96}}{0.08}
=\frac{\sqrt{}}{0.08}
$